(3/5)^(x+1)=25/9

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Solution for (3/5)^(x+1)=25/9 equation: 



(3/5)^(x+1)=25/9

We move all terms to the left:

(3/5)^(x+1)-(25/9)=0



Domain of the equation: 5)^(x+1)!=0

x∈R



We add all the numbers together, and all the variables

(+3/5)^(x+1)-(+25/9)=0

We get rid of parentheses

(+3/5)^(x+1)-25/9=0

We calculate fractions


()/5^x+(-125x)/5^x=0

We multiply all the terms by the denominator


(-125x)+()=0

We add all the numbers together, and all the variables

(-125x)=0

We get rid of parentheses

-125x=0

x=0/-125

x=0

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